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Factorise: 64a2b - 144b3 - Mathematics

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Question

factorise:  64a2b - 144b3 

Sum

Solution

64a2b - 144b3 

= 16b (4a2 - 9b2)

= 16b [(2a)2 - (3b)2] 

= 16b (2a + 3b)(2a - 3b)

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Factorisation of Trinomials
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Q 6.3
Chapter 13: Factorisation - Exercise 13 (F) [Page 163]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 13 Factorisation
Exercise 13 (F) | Q 6.3 | Page 163

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