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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Factorise: (7y2 – 19y – 6) - Mathematics

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Question

Factorise: (7y2 – 19y – 6)

Sum

Solution

7y2 – 19y – 6 is of the form ax2 + bx + c where a = 7, b = – 19, c = – 6

Product = – 42 Sum = – 19
1 × – 42 = – 42 1 + (– 42) = – 41
2 × – 21 = – 42 2 + (– 21) = – 19

The product a × c = 7 × – 6 = – 42

sum b = – 19

The middle term – 19 y can be written as – 21y + 2y

7y2 – 19y – 6 = 7y2 – 21y + 2y – 6

= 7y(y – 3) + 2(y – 3)

= (y – 3)(7y + 2)

7y2 – 19y – 6 = (y – 3)(7y + 2)

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Chapter 3: Algebra - Exercise 3.5 [Page 97]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 3 Algebra
Exercise 3.5 | Q 5 | Page 97
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