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Question
Factorise:
a3 - 27
Sum
Solution
a3 - 27
= (a)3 - (3)3
= (a - 3)[(a)2 + a × 3 + (3)2] ...[∵ a3 - b3 = (a - b)(a2 + ab + b2)]
= (a - 3)[a2 + 3a + 9]
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Method of Factorisation : the Sum Or Difference of Two Cubes
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