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Question
Find the 6th term form the end of the AP 17, 14, 11, ……, (-40).
Solution
Here, a = 7 and d = (14-17) = -3, l = (-40) and n = 6
Now, nth term from the end =[l-(n-1)d]
6th term from the end = [(-40)-(6-1) × (-3)]
= [ -40 + (5× 3)]=(-40+15)/-25
Hence, the 6th term from the end is –25.
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