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Find the 8th Term in the Expansion of ( X 3 / 2 Y 1 / 2 − X 1 / 2 Y 3 / 2 ) 10 - Mathematics

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Question

Find the 8th term in the expansion of  \[\left( x^{3/2} y^{1/2} - x^{1/2} y^{3/2} \right)^{10}\]

  

Solution

We need to find the 8th term in the given expression.

\[\because T_8 = T_{7 + 1}\]
\[\therefore T_8 =^{10}{}{C}_7 ( x^{3/2} y^{1/2} )^{10 - 7} ( - x^{1/2} y^{3/2} )^7 \]
\[ = - \frac{10 \times 9 \times 8  } {3 \times 2} x^{9/2} y^{3/2} \left( x^{7/2} y^{21/2} \right) \]
\[ = - 120 x^8 y^{12}\]
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Chapter 18: Binomial Theorem - Exercise 18.2 [Page 37]

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RD Sharma Mathematics [English] Class 11
Chapter 18 Binomial Theorem
Exercise 18.2 | Q 4 | Page 37

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