Advertisements
Advertisements
Question
Find a critical angle for glass and water pair, given the refractive index of glass, is 1 ·62 and that of water is 1 ·33.
Solution
`omega^(mug)` = R.I of glass w.r.t water
=`(mug)/(muomega)`
`omega^(mug) = 1.62/1.33`
∴ sin c = `133/1.62 = 0.82`
∴ c = Critical angle = sin-1 0.82 = 55°
APPEARS IN
RELATED QUESTIONS
Derive Snell’s law on the basis of Huygen’s wave theory when the light is travelling from a denser to a rarer medium.
Calculate the speed of light in a medium whose critical angle is 45°. Does critical angle for a given pair of media depend on the wavelength of incident light ? Give reason.
Derive Snell’s law of refraction using Huygens’s wave theory.
Answer the following question.
Define the term, "refractive index" of a medium. Verify Snell's law of refraction when a plane wavefront is propagating from a denser to a rarer medium.
A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.)
According to Snell’s law, ______.
For small angles Snell’s law becomes ______.
Using Huygen’s wave theory of light, prove Snell’s law of refraction of light.
Draw the shape of refracted wavefront when the plane incident wave undergoes refraction from optically denser medium to rarer medium. Hence prove Snell’s law of refraction.
A ray of light is incident on a glass prism of refractive index µ and refracting angle A. If it just suffers total internal reflection at the other face, obtain a relation between the angle of incidence, angle of prism and critical angle.
