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Question
Find the acid value of the given oil whose 20 ml required 2.8 ml of N/10 KOH during titration .( Density of oil =0.86 g/ml )
Solution
Given : VKOH = 2.8 ml , VOil = 20 ml , N = 1/10 , DOil = 0.86 g/ml
To Find : Acid Value
Formula : Acid Value = 56 x VKOH x N /WOil
Solution : WOil = DOil x VOil = 0.86 x 20 = 17.2 g
Acid Value = 56 x 2.8 x 0.1 /17.2 mg of KOH
= 0.912 mg of KOH
The Acid Value of the given oil is 0.912 mg of KOH .
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