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Question
Find the discriminant of the quadratic equation \[3\sqrt{3} x^2 + 10x + \sqrt{3} = 0\].
Solution
Given that quadric equation is \[3\sqrt{3} x^2 + 10x + \sqrt{3} = 0\].
Then, find the value of discrimenant.
Here, `a =3sqrt3 , b = 10 and , c = sqrt 3`
As we know that discrimenant D = b^2 - 4ac
Putting the value of `a =3sqrt3 , b = 10 and , c = sqrt 3`
` = (10)^2 - 4 xx 3 sqrt3 xx sqrt3`
= 100 - 36
= 64
Thus, the value of discrimenant be D = 64 .
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