Advertisements
Advertisements
Question
Find the greatest common factor of the terms in each of the following expression:
3a2b2 + 4b2c2 + 12a2b2c2
Solution
The expression has three monomials: 3a2b2, 4b2c2 and 12a2b2c2.
The numerical coefficients of the given monomials are 3, 4 and 12. The greatest common factor of 3, 4 and 12 is 1.
The common literal appearing in the three monomials is b.
The smallest power of b in the three monomials is 2.
The monomial of common literals with the smallest powers is b2.
Hence, the greatest common factor is b2.
APPEARS IN
RELATED QUESTIONS
Factorize each of the following algebraic expressions:
16(2l − 3m)2 −12(3m − 2l)
Factorize each of the following algebraic expressions:
6(a + 2b) −4(a + 2b)2
Factorize each of the following expressions:
p2q − pr2 − pq + r2
Factorize each of the following algebraic expression:
a2 + 2ab + b2 − 16
Factorize each of the following algebraic expressions:
x2 + 9y2 − 6xy − 25a2
Factorize each of the following algebraic expression:
x2 − y2 + 6y − 9
Factorize each of the following algebraic expression:
x2 + 12x − 45
Factorize each of the following algebraic expression:
40 + 3x − x2
Factorize each of the following algebraic expression:
a2 + 14a + 48
Factorise the following expression.
`"x"^2-1/"x"^2`
