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Question
Find k if the equations x + y + z = 1, 3x – y – z = 4, x + 5y + 5z = k are inconsistent
Solution
x + y + z = 1
3x – y – z = 4
x + 5y + 5z = k
The matrix equation corresponding to the given system is
`[(1, 1, 1),(3, -1, -1),(1, 5, 5)] [(x),(y),(z)] = [(1), (4), ("k")]`
A X = B
Augmented Matrix [A, B] |
Elementary Transformation |
`[(1, 1, 1, 1),(3, -1, -1, 4),(1, 5, 5, "k")]` | |
`∼[(1, 1, 1, 1),(0, -4, -4, 1),(0, 4, 4, "k" - 1)]` | `{:("R"_2 -> "R"_2 - 3"R"_1),("R"_3 -> "R"_3 - "R"_1):}` |
`∼[(1, 1, 1, 1),(0, -4, -4, 1),(0, 0, 0, "k")]` | `{:"R"_3 -> "R"_3 + R_2:}` |
Obviously, the last equivalent matrix is in the echelon form.
Since the equations are inconsistent
p(A) ≠ p(A, B)
Here p(A) = 2 but p(A, B) should not equal to 2
∴ k ≠ 0
The equations are inconsistent when k assume any real value other than 0.
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