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Find the Probability that a Leap Year Selected at Random Will Contain 53 Sundays. - Mathematics

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Question

Find the probability that a leap year selected at random will contain 53 Sundays.

Short Note
Sum

Solution

A leap year has 366 days with 52 weeks and 2 days.

Now, 52 weeks conatins 52 sundays.

The remaining two days can be:

  1. Sunday and Monday
  2. Monday and Tuesday
  3. Tuesday and Wednesday
  4. Wednesday and Thursday
  5. Thursday and Friday
  6. Friday and Saturday
  7. Saturday and Sunday

Out of these 7 cases, there are two cases favouring it to be Sunday.

∴ P(a leap year having 53 Sundays) = `("Number of favourable outcomes")/"Number of all possible outcomes"`

`= 2/7`

Thus, the probability that a leap year selected at random will contain 53 Sundays is `2/7`.

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Chapter 15: Probability - Exercise 15B [Page 699]

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RS Aggarwal Mathematics [English] Class 10
Chapter 15 Probability
Exercise 15B | Q 25 | Page 699

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