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Question
Find the probability that a leap year selected at random will contain 53 Sundays.
Solution
A leap year has 366 days with 52 weeks and 2 days.
Now, 52 weeks conatins 52 sundays.
The remaining two days can be:
- Sunday and Monday
- Monday and Tuesday
- Tuesday and Wednesday
- Wednesday and Thursday
- Thursday and Friday
- Friday and Saturday
- Saturday and Sunday
Out of these 7 cases, there are two cases favouring it to be Sunday.
∴ P(a leap year having 53 Sundays) = `("Number of favourable outcomes")/"Number of all possible outcomes"`
`= 2/7`
Thus, the probability that a leap year selected at random will contain 53 Sundays is `2/7`.
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