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Question
Find the probability that a number selected at random from the numbers 1, 2, 3, ..., 35 is a Multiple of 3 or 5
Solution
Total no. of possible outcomes = 35 {1, 2, 3, …. 35}
E ⟶ event of getting no which is multiple of 3 or 5
No. of favourable outcomes = 16 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 5, 10, 20, 25, 35}
Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) = 16/35
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