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Question
Find the slope of a line passing through the following pair of points
(5pq,p2q) and (5qr,qr2)
Solution
A(x1,y1) = A(5pq, p2q)
B(x2, y2) = B(5qr, qr2)
Slope of line AB = `("y"_2 - "y"_1)/("x"_2 - "x"_1)``
= `("qr"^2 - "p"^2"q")/(5"qr" - 5"pq")`
= `("q"("r"^2 - "p"^2))/(5"q"("r" - "p"))`
= `1/5 (("r" - "p")("r" + "p"))/(("r" -"p"))`
= `("r" + "p")/5`
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