Advertisements
Advertisements
Question
Find the slope of a line perpendicular to the foloowing line x - `(3"y")/2 + 1 = 0`
Solution
When two lines are perpendicular to each other the product of their slope is -1.
i.e m1 x m2 = -1
x - `(3"y")/2 + 1 = 0`
`(3"y")/2` = x + 1
y = `2/3"x" + 2/3`
m1 = `2/3`
Slope of required line (m2) = `-1/"m"_1 = (-3)/2`
APPEARS IN
RELATED QUESTIONS
Find the equation of the line passing through (−5, 7) and parallel to x-axis
Find the equation of the line passing through (−5, 7) and parallel to y-axis
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the line through C and parallel to AB.
Point P divides the line segment joining the points A(8, 0) and B(16, –8) in the ratio 3 : 5. Find its co-ordinates of point P. Also, find the equation of the line through P and parallel to 3x + 5y = 7.
From the given figure, find:
- the co-ordinates of A, B and C.
- the equation of the line through A and parallel to BC.
A(8, −6), B(−4, 2) and C(0, −10) are vertices of a triangle ABC. If P is the mid-point of AB and Q is the mid-point of AC, use co-ordinate geometry to show that PQ is parallel to BC. Give a special name to quadrilateral PBCQ.
ABCD is a parallelogram where A(x, y), B(5, 8), C(4, 7) and D(2, −4). Find:
- co-ordinates of A.
- equation of diagonal BD.
Find the slope of a line perpendicular to the foloowing line `(3"x")/4 -"y" = 5`
Find the value of a line perpendicular to the given line 3x+4y = 13
Find the value of a line perpendicular to the given line 9x-3y = 5
