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प्रश्न
Find the slope of a line perpendicular to the foloowing line x - `(3"y")/2 + 1 = 0`
उत्तर
When two lines are perpendicular to each other the product of their slope is -1.
i.e m1 x m2 = -1
x - `(3"y")/2 + 1 = 0`
`(3"y")/2` = x + 1
y = `2/3"x" + 2/3`
m1 = `2/3`
Slope of required line (m2) = `-1/"m"_1 = (-3)/2`
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