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Question
Find the area enclosed by the following figure:
Solution
The given shape contains a rectangle and a semi-circle
∴ Area of rectangle = l × b = (10.2 × 1.5) cm2 = 15.3 cm2
Here, Diameter of semi-circle = (10.2 – 3.9)cm = 6.3 cm
So, radius = `"Diameter"/2 = 6.3/2` = 3.15 cm
∴ Area of semicircle = `1/2 πr^2` = `22/7 xx 1/2 xx 3.15 xx 3.15` = 15.59 cm2
∴ Total area = Area of rectangle + Area of semi-circle = 15.3 + 15.59 = 30.89 cm2
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