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Question
Find the area enclosed by the following figure:
Solution
The given shape has a triangle and a rectangle
For rectangle, l = 13 cm and b = 4 cm
∴ Area of rectangle = l × b = 13 × 4 = 52 cm2
For triangle, base (b) = 5 cm
and height (h) = (16 – 4) cm = 12 cm
∴ Area of triangle = `1/2` × b × h = `1/2` × 5 × 12 = 30 cm2
∴ Total area enclosed by the shape = (52 + 30) cm2 = 82 cm2.
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