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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Find the area of the shaded part in the following figure. (π = 3.14) - Mathematics

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Question

Find the area of the shaded part in the following figure. (π = 3.14)

Sum

Solution

Area of the shaded part = Area of 4 quadrant circles of radius `10/2` cm

= `4 xx 1/4 xx pi"r"^2`

= `3.14  xx 10/2 xx 10/2  "cm"^2`

= `314/4  "cm"^2`

= 78.5 cm2

Area of the shaded part = 78.5 cm2

Area of the unshaded part = Area of the square – Area of shaded part

= a2 – 78.5 cm2 = (10 × 10) – 78.5 cm2

= 100 – 78.5 cm2 = 21.5 cm2

Area of the unshaded part = 21.5 cm2 ...(approximately)

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Perimeter and Area of Combined Shapes
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Chapter 2: Measurements - Exercise 2.2 [Page 66]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 2 Measurements
Exercise 2.2 | Q 2. (i) | Page 66
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