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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ८

Find the area of the shaded part in the following figure. (π = 3.14) - Mathematics

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प्रश्न

Find the area of the shaded part in the following figure. (π = 3.14)

बेरीज

उत्तर

Area of the shaded part = Area of 4 quadrant circles of radius `10/2` cm

= `4 xx 1/4 xx pi"r"^2`

= `3.14  xx 10/2 xx 10/2  "cm"^2`

= `314/4  "cm"^2`

= 78.5 cm2

Area of the shaded part = 78.5 cm2

Area of the unshaded part = Area of the square – Area of shaded part

= a2 – 78.5 cm2 = (10 × 10) – 78.5 cm2

= 100 – 78.5 cm2 = 21.5 cm2

Area of the unshaded part = 21.5 cm2 ...(approximately)

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Perimeter and Area of Combined Shapes
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पाठ 2: Measurements - Exercise 2.2 [पृष्ठ ६६]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
पाठ 2 Measurements
Exercise 2.2 | Q 2. (i) | पृष्ठ ६६
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