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प्रश्न
Find the perimeter and area of the figure given below. `(pi = 22/7)`
उत्तर
Perimeter = sum of outside lengths
Length of the arc of quadrant circle = `1/4 xx 2pi"r units"`
= `1/2 xx 22/7 xx 3.5 "cm"`
= 11 × 0.5 cm = 5.5 cm
∴ Length of arc of 2 sectors 2 × 5.5 cm
= 11 cm
∴ Perimeter P = 11 + 6 + 3.5 + 6 + 35 cm
P = 30 cm
Area Area of 2 quadrant circle + Area of a rectangle.
= `2 xx 1/4pi"r"^2 + "lb" "sq.units"`
= `(1/2 xx 22/7 xx 3.5 xx 3.5) + (6 xx 3.5) "cm"^2`
= (11 × 3.5 × 0.5) + 21 cm2
= (19.25 + 21) cm2 = 40.25 cm2
∴ Area = 40.25 cm2 (approx)
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