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Question
Find the area of the shaded region where ABC is a quadrant of radius 5cm and a semicircle is drawn with BC as diameter.
Options
8.8 cm2
7.14cm2
12.5cm2
19.64cm2
MCQ
Solution
12.5cm2
Explanation:
Area of the shaded region = Area of semicircle-Area of the segment of the sector BAC
Area of the semicircle with BC as diameter = `1/2 xx 22/7 xx 5/sqrt2 xx 5/sqrt2`
`= 19.64 "cm"^2` .....(i)
Area of segment = Area of quadrant – Area of ΔABC
`90/360 xx 22/7 xx 5^2 - 1/2 xx 5 xx 5`
`= 19.64 - 12.5`
`= 7.14 "cm"^2`....(ii)
Area of the shaded region = (i) – (ii)
`= 19.64 - 7.14`
`= 12.5 "cm"^2`
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