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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Find the central angle of the sectors whose measures are given below. π(π=227) area = 462 cm2, r = 21 cm - Mathematics

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Question

Find the central angle of the sectors whose measures are given below. `(π = 22/7)`

area = 462 cm2, r = 21 cm

Sum

Solution

area = 462 cm2, r = 21 cm

Radius of the Sector = 21 cm

Area of the sector = 462 cm

`"lr"/2` = 462

`("l" xx 21)/2` = 462

l = `(462 xx 2)/21`

l = 22 × 2

Length of the arc l = 44 cm

`(theta^circ)/(360^circ) xx 2pi"r"` = 44 cm

`(theta^circ)/(360^circ) xx 2 xx 22/7 xx 21` = 44 cm

θ° = `(44 xx 360 xx 7)/(2 xx 22 xx 21)`

θ° = 120°

∴ Central angle of the sector = 120° 

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Chapter 2: Measurements - Exercise 2.1 [Page 59]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 2 Measurements
Exercise 2.1 | Q 6. (i) | Page 59
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