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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Find the central angle of the shaded sectors (each circle is divided into equal sectors). Sectors Central angle of each sector (θ°) - Mathematics

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Question

Find the central angle of the shaded sectors (each circle is divided into equal sectors).

Sectors
Central angle
of each sector (θ°)
       
Sum

Solution

Sectors
Central angle
of each sector (θ°)

Number of equal parts
n = 2

θ° = `(360^circ)/"n" = (360^circ)/2`

θ° = 180°

Number of equal parts
n = 5

θ° = `(360^circ)/"n"`

θ° = `(360^circ)/2`

θ° = 72°

Number of equal parts
n = 8

θ° = `(360^circ)/"n"`

θ° = `(360^circ)/8`

θ° = 45°

Number of equal parts
n = 10

θ° = `(360^circ)/"n"`

θ° = `(360^circ)/10`

θ° = 36°

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Chapter 2: Measurements - Exercise 2.1 [Page 58]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 2 Measurements
Exercise 2.1 | Q 3 | Page 58
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