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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ८

Find the central angle of the shaded sectors (each circle is divided into equal sectors). Sectors Central angle of each sector (θ°) - Mathematics

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प्रश्न

Find the central angle of the shaded sectors (each circle is divided into equal sectors).

Sectors
Central angle
of each sector (θ°)
       
योग

उत्तर

Sectors
Central angle
of each sector (θ°)

Number of equal parts
n = 2

θ° = `(360^circ)/"n" = (360^circ)/2`

θ° = 180°

Number of equal parts
n = 5

θ° = `(360^circ)/"n"`

θ° = `(360^circ)/2`

θ° = 72°

Number of equal parts
n = 8

θ° = `(360^circ)/"n"`

θ° = `(360^circ)/8`

θ° = 45°

Number of equal parts
n = 10

θ° = `(360^circ)/"n"`

θ° = `(360^circ)/10`

θ° = 36°

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अध्याय 2: Measurements - Exercise 2.1 [पृष्ठ ५८]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
अध्याय 2 Measurements
Exercise 2.1 | Q 3 | पृष्ठ ५८
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