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प्रश्न
Match the following:
| Column A | Column B |
| (i) Area of a circle | (a) `1/4 pi"r"^2` |
| (ii) Circumference of a circle | (b) (π + 2)r |
| (iii) Area of the sector of a circle | (c) πr2 |
| (iv) Circumference of a semicircle | (d) 2πr |
| (v) Area of a quadrant of a circle | (e) `theta^circ/360^circ xx pi"r"^2` |
उत्तर
| Column A | Column B |
| (i) Area of a circle | (c) πr2 |
| (ii) Circumference of a circle | (d) 2πr |
| (iii) Area of the sector of a circle | (e) `theta^circ/360^circ xx pi"r"^2` |
| (iv) Circumference of a semicircle | (b) (π + 2)r |
| (v) Area of a quadrant of a circle | (a) `1/4 pi"r"^2` |
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संबंधित प्रश्न
The radius of a circle is 10 cm. The measure of an arc of the circle is 54°. Find the area of the sector associated with the arc. (\[\pi\]= 3.14 )
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In the given figure, seg AB is a chord of a circle with centre P. If PA = 8 cm and distance of chord AB from the centre P is 4 cm, find the area of the shaded portion. ( \[\pi\] = 3.14, \[\sqrt{3}\]= 1.73 )
In Δ ABC, if ∠ A = 65° ; ∠ B = 40° then find the measure of ∠ C.
A circle is inscribed in square ABCD of side 14 cm. Complete the following activity to find the area of the shaded portion.
Activity:
Area of square ABCD = ______
= 142
= 196 cm2
Area of circle = πr2 = `22/7xx 7^2`
= ____ cm2
Area of shaded portion = Area of square ABCD – Area of circle
= 196 – _______
= _____ cm2
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