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Question
Find the cube of: `2"x"+1/"x"`
Sum
Solution
`(2"x"+1/"x")^3`
`=(2"x")^3+(1/"x")^3+3xx2"x"xx1/"x"(2"x"+1/"x")`
`=8"x"^3+1/"x"^3+6(2"x"+1/"x")`
`= 8"x"^3+1/"x"^3+12"x"+6/"x"`
`=8"x"^3+12"x"+6/"x"+1/"x"^3`
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Cubes of Binomials
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