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Question
Find the first three terms to the sequence, whose nth term is tn = 4n - 3
Solution
tn = 4n - 3
∴ t1 = 4(1) - 3 = 4 - 3 = 1
∴ t2 = 4(2) - 3 = 8 - 3 = 5
∴ t3 = 4(3) - 3 = 12 - 3 = 9
∴ The first three terms are 1 , 5 and 9
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