Advertisements
Advertisements
Question
Find the greatest number which divides 615 and 963, leaving the remainder 6 in each case.
Solution
Because the remainder is 6, we have to find the number that exactly divides (615 - 6) and (963 - 6).
Required number = HCF of 609 and 957
Therefore, the required number is 87.
APPEARS IN
RELATED QUESTIONS
Test the divisibility of the following number by 3:
79124
Test the divisibility of the following numbers by 5:
35208
Test the divisibility of the following number by 11:
66311
Test the divisibility of the following number by 11:
137269
In the following number, replace * by the smallest number to make it divisible by 9:
2*135
In the following number, replace * by the smallest number to make it divisible by 9:
91*67
Test the divisibility of 10203574 by 4.
Write (T) for true and (F) for false against the following statement:
If a number is divisible by 3 and 7, it must be divisible by 21.
Write (T) for true and (F) for false against the following statement:
If a number divides two numbers exactly, it must divide their sum exactly.
The smallest number which when diminished by 3 is divisible by 14, 28, 36 and 45, is