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Find the HCF of the numbers in each of the following, using the prime factorization method:272, 425 - Mathematics

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Question

Find the HCF of the numbers in each of the following, using the prime factorization method:
272, 425

Sum

Solution

Given numbers are 272 and 425.
We have:

Now, 272 = 2 × 2× 2 × 2 × 17
425 = 5 × 5 × 17
∴ The required HCF is 17.

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Chapter 2: Factors and Multiples - Exercise 2D [Page 36]

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RS Aggarwal Mathematics [English] Class 6
Chapter 2 Factors and Multiples
Exercise 2D | Q 7 | Page 36

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