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Find the HCF of the numbers in each of the following, using the prime factorization method:72, 108, 180 - Mathematics

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Question

Find the HCF of the numbers in each of the following, using the prime factorization method:
72, 108, 180

Sum

Solution

The given numbers are 72, 108 and 180
We have:

Now, 72=2 × 2 × 2 × 3 × 3 = 23 × 32
108 = 2 × 2 × 3 × 3 × 3 = 22 × 33
180 = 2 × 2 × 3 ×3 × 5 = 22 × 3× 5
∴ HCF =22×32 =36

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Chapter 2: Factors and Multiples - Exercise 2D [Page 36]

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RS Aggarwal Mathematics [English] Class 6
Chapter 2 Factors and Multiples
Exercise 2D | Q 4 | Page 36

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