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Question
Find the HCF set of numbers using prime factorisation method.
27, 45, 81
Solution
27, 45, 81
Prime factorisation of 27 = 3 × 3 × 3
Prime factorisation of 45 = 3 × 3 × 5
Prime factorisation of 81 = 3 × 3 × 3 × 3
Common factors of 27, 45, 81 = 3 × 3 = 9
HCF (27, 45, 81) = 9
| 3 | 27 |
| 3 | 9 |
| 3 | 3 |
| 1 |
| 3 | 45 |
| 3 | 15 |
| 5 | 5 |
| 1 |
| 3 | 81 |
| 3 | 27 |
| 3 | 9 |
| 3 | 3 |
| 1 |
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