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Find the intercepts cut off by the plane 2x+y-z = 5 -

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Question

Find the intercepts cut off by the plane `2x + y - z` = 5

Options

  • `(-5, 5/2, 5)`

  • `(5/2, 5, -5)`

  • `(5, -5, 5/2)`

  • None of these

MCQ

Solution

`(5/2, 5, -5)`

Explanation:

Equation of the plane is `2x + 2y - z` = 5

Dividing by 5,

`2/5 xx y/5 - z/5` = 1

or `x/5 + y/5 + 2/5` = 1, Which is of the form

`x/a + y/a + z/c` = 1 Where a, b, c are the intercepts.

The intercepts on the axes ox, oy, oz are `5/2, 5, -5` respectively.

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