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Question
Find the least number which when divided by 25, 40, and 60 leaves 9 as the remainder in each case.
Solution
25, 40, and 60 exactly divides the least number that is equal to their LCM.
So, the required number that leaves 9 as a remainder will be LCM + 9.
Finding the LCM:
LCM = 23 × 3 × 52 = 600
∴ Required number = 600 + 9 = 609
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