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Question
Reduce each of the following fraction to the lowest term:
`161/207`
Solution
`161/207`
To reduce the given fraction to its lowest term, we will divide the numerator and the denominator by their HCF.
Now, we will find the HCF of 161 and 207.
∴ HCF = 23
Dividing the numerator and the denominator by the HCF, we get:
`[161÷23]/[207÷23]=7/9`
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