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Question
Find the least number which when divided by 6, 15 and 18 leave the remainder of 5 in each case.
Solution
LCM of 6, 15, 18
| 2 | 6, 15, 18 |
| 3 | 3, 15, 9 |
| 3 | 1, 5, 3 |
| 5 | 1, 5, 1 |
| 1, 1, 1 |
LCM = 2 × 3 × 3 × 5 = 90
Required number = 90 + 5 = 95
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