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Question
Find the mean proportional to (x – y) and (x3 – x2y).
Solution
Let the mean proportional to (x – y) and (x3 – x2y) be n.
`=>` (x – y), n, (x3 – x2y) are in continued proportional
`=>` (x – y) : n = n : (x3 – x2y)
`=>` n2 = x2(x – y)(x – y)
`=>` n2 = x2(x – y)2
`=>` n = x(x – y)
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