English

Find the number of pairs of observations from the following data, r = 0.15, σy = 4, ∑(xi-x¯)(yi-y¯) = 12, ∑(xi-x¯)2 = 40. - Mathematics and Statistics

Advertisements
Advertisements

Question

Find the number of pairs of observations from the following data,
r = 0.15, `sigma_"y"` = 4, `sum("x"_"i" - bar"x")("y"_"i" - bar"y")` = 12, `sum("x"_"i" - bar"x")^2` = 40.

Sum

Solution

Given, r = 0.15, `sigma_"y"` = 4, `sum("x"_"i" - bar"x")("y"_"i" - bar"y") `= 12, `sum("x"_"i" - bar"x")^2` = 40

Since, `sigma_"x" = sqrt(1/"n" sum("x"_"i" - bar"x")^2) = sqrt(40/"n"`

Cov (x, y) = `1/"n" sum("x"_"i" - bar"x")("y"_"i" - bar"y")`

= `1/"n" xx 12`

∴ Cov (x, y) = `12/"n"`

Since, r = `("Cov (x, y)")/(sigma_"x" sigma_"y")`

∴ 0.15 = `(12/"n")/(sqrt(40/"n") xx 4)`

∴ 0.15 = `3/("n" xx sqrt(40/"n")`

∴ 0.15 = `1/(sqrt("n") xx sqrt(40)`
Squaring on both the sides, we get

0.0025 = `1/("n" xx 40)`

∴ n = `1/(0.0025 xx 40)`

= `10000/(25 xx 40)`

= `10000/1000`

∴ n = 10

shaalaa.com
Concept of Correlation Coefficient
  Is there an error in this question or solution?
Chapter 5: Correlation - Miscellaneous Exercise 5 [Page 63]

APPEARS IN

RELATED QUESTIONS

Find correlation coefficient between x and y series for the following data.
n = 15, `bar"x"` = 25, `bar"y"` = 18, σx = 3.01, σy = 3.03, `sum("x"_"i" - bar"x") ("y"_"i" - bar"y")` = 122


The correlation coefficient between two variables x and y are 0.48. The covariance is 36 and the variance of x is 16. Find the standard deviation of y.


In the following data one of the value y of is missing. Arithmetic means of x and y series are 6 and 8 respectively. `(sqrt(2) = 1.4142)`

x 6 2 10 4 8
y 9 11 ? 8 7

Calculate the correlation coefficient


Find correlation coefficient from the following data. `["Given:" sqrt(3) = 1.732]`

x 3 6 2 9 5
y 4 5 8 6 7

Correlation coefficient between x and y is 0.3 and their covariance is 12. The variance of x is 9, Find the standard deviation of y.


Two series of x and y with 50 items each have standard deviations of 4.8 and 3.5 respectively. If the sum of products of deviations of x and y series from respective arithmetic means is 420, then find the correlation coefficient between x and y.


A sample of 5 items is taken from the production of a firm. Length and weight of 5 items are given below. [Given : `sqrt(0.8823)` = 0.9393]

Length (cm) 3 4 6 7 10
Weight (gm.) 9 11 14 15 16

Calculate the correlation coefficient between length and weight and interpret the result.


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between 2x and y


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between `"x"/2` and y


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x and 3y


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x – 5 and y – 3


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x + 7 and y + 9


If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between `("x" - 5)/7` and `("y" - 3)/8`?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×