Advertisements
Advertisements
Question
Given that r = 0.4, `sigma_"y"` = 3, `sum("x"_"i" - bar"x")("y"_"i" - bar"y")` = 108, `sum("x"_"i" - bar"x")^2` = 900. Find the number of pairs of observations.
Solution 1
Given, r = 0.4, `sigma_y = 3, sum(x_"i" - bar(x))(y_"i" - bar(y)) = 108, sum(x_"i" - bar(x))^2 = 900`
Cov (X, Y) = `1/"n" sum(x_"i" - bar(x))(y_"i" - bar(y))`
= `1/"n" xx 108`
∴ Cov (X, Y) = `108/"n"`
`sigma_x = sqrt(1/"n" xx sum(x_"i" - bar(x))^2`
= `sqrt(1/"n" xx 900)`
= `sqrt(900/"n") = 30/sqrt("n")`
Since, r = `("Cov (X, Y)")/(sigma_x sigma_y)`
∴ 0.4 = `(108/"n")/(30/sqrt("n") xx 3)`
∴ 0.4 = `108/"n" xx sqrt("n")/(30 xx 3)`
∴ 0.4 = `12/(10sqrt("n")`
∴ `sqrt("n") = 12/4` = 3
∴ n = 9.
Solution 2
Given, r = 0.4, `sigma_"y"` = 3, `sum("x"_"i" - bar"x")("y"_"i" - bar"y")` = 108, `sum("x"_"i" - bar"x")^2` = 900.
Cov (x, y) = `1/"n" sum("x"_"i" - bar"x"("y"_"i" - bar"y")`
= `1/"n" xx 108`
∴ Cov (x, y) = `108/"n"`
`sigma_"x" = sqrt(1/"n" xx sum("x"_"i" - bar"x")^2`
= `sqrt(1/"n" xx 900)`
= `sqrt(900/"n") = 30/sqrt("n")`
Since, r = `("Cov (x, y)")/(sigma_"x" sigma_"y")`
∴ 0.4 = `(108/"n")/(30/sqrt("n") xx 3)`
∴ 0.4 = `108/"n" xx sqrt("n")/(30 xx 3)`
∴ 0.4 = `12/(10sqrt("n")`
∴ `sqrt("n") = 12/4` = 3
∴ n = 9
APPEARS IN
RELATED QUESTIONS
Find correlation coefficient between x and y series for the following data.
n = 15, `bar"x"` = 25, `bar"y"` = 18, σx = 3.01, σy = 3.03, `sum("x"_"i" - bar"x") ("y"_"i" - bar"y")` = 122
The correlation coefficient between two variables x and y are 0.48. The covariance is 36 and the variance of x is 16. Find the standard deviation of y.
In the following data one of the value y of is missing. Arithmetic means of x and y series are 6 and 8 respectively. `(sqrt(2) = 1.4142)`
x | 6 | 2 | 10 | 4 | 8 |
y | 9 | 11 | ? | 8 | 7 |
Calculate the correlation coefficient
Find correlation coefficient from the following data. `["Given:" sqrt(3) = 1.732]`
x | 3 | 6 | 2 | 9 | 5 |
y | 4 | 5 | 8 | 6 | 7 |
Correlation coefficient between x and y is 0.3 and their covariance is 12. The variance of x is 9, Find the standard deviation of y.
Find the number of pairs of observations from the following data,
r = 0.15, `sigma_"y"` = 4, `sum("x"_"i" - bar"x")("y"_"i" - bar"y")` = 12, `sum("x"_"i" - bar"x")^2` = 40.
Given the following information, `sum"x"_"i"^2` = 90, `sum"x"_"i""y"_"i"` = 60, r = 0.8, `sigma_"y"` = 2.5, where xi and yi are the deviations from their respective means, find the number of items.
If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between 2x and y
If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between `"x"/2` and y
If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x and 3y
If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x – 5 and y – 3
If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between x + 7 and y + 9
If the correlation coefficient between x and y is 0.8, what is the correlation coefficient between `("x" - 5)/7` and `("y" - 3)/8`?
In the calculation of the correlation coefficient between the height and weight of a group of students of a college, one investigator took the measurements in inches and pounds while the other investigator took the measurements in cm. and kg. Will they get the same value of the correlation coefficient or different values? Justify your answer.