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Question
Find the point on the y-axis which is equidistant from the points (S, - 2) and (- 3, 2).
Solution
Since the point is on y-axis so, X - coordinate is zero
Let the point be (0, y)
It's distance from A{5, - 2) and B(-3, 2) are equal
∴ `sqrt((0 - 5)^2 +( y+2)^2) = sqrt((0+3)^2 +(y - 2)^2)`
⇒ 25 + Y2 + 4y + 4 = 9 + y2 - 4y+4 [squaring both sides]
⇒ 4y + 29= -4y + 13
⇒ 4y+ 4y=13-29
⇒ 8y = - 16 ∴y =`(-16)/8` = -2
Thus ,the point is (0, -2).
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