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Find the Probability that Leap Year Selected at Random, Will Contain 53 Sundays - Mathematics

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Question

Find the probability that leap year selected at random, will contain 53 Sundays.

Sum

Solution

In a leap there are 366 days. In 366 days, we have 52 weeks and 2 days, Thus we can say that leap year has always 52 sundays.

The remaining two days can be
(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday  
From above it is clear that there are 7 elementary events associated with this random experiment.

Clearly, the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.

n(E) = 2
P(E) = 2
∴ P(E) = `"n(E)"/"n(S)" = 2/7`.

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Chapter 20: Probability - Exercise

APPEARS IN

ICSE Mathematics [English] Class 10
Chapter 20 Probability
Exercise | Q 20

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