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Question
Ramesh chooses a date at random in January for a party.
| January | |||||
| Mon | 6 | 13 | 20 | 27 | |
| Tue | 7 | 14 | 21 | 28 | |
| Wed | 1 | 8 | 15 | 22 | 29 |
| Thurs | 2 | 9 | 16 | 23 | 30 |
| Fri | 3 | 10 | 17 | 24 | 31 |
| Sat | 4 | 11 | 18 | 25 | |
| Sun | 5 | 12 | 19 | 26 | |
Find the probability that he chooses:
- a Wednesday
- a Friday
- a Tuesday or a Saturday.
Solution
Number of possible outcomes = number of day in the month = 31
n(S) = 31
i. E = event of selection of a Wednesday = {1, 8, 15, 22, 29}
n(E) = 5
Probability of selection of a Wednesday = P(S)
= `"n(E)"/"n(S)"`
= `5/31`
ii. E = event of selection of a Friday = {3, 10, 17, 24, 31}
n(E) = 5
Probability of selection of a Friday = P(S)
= `"n(E)"/"n(S)"`
= `5/31`
iii. E = event of selection of a Tuesday or a Saturday = {4, 7, 11, 14, 18, 21, 25, 28}
n(E) = 8
Probability of selection of a Tuesday or a Saturday = P(S)
= `"n(E)"/"n(S)"`
= `8/31`
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