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Question
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by x – 2
Solution
f(x) = 2x3 – 3x2 + 4x + 7
Let x – 2 = 0,
then x = 2
Substituting value of x in f(x)
f(2) = 2 (2)3 – 3 (2)2 + 4 (2) + 7
= 2 × 8 – 3 × 4 + 4 × 2 + 7
= 16 – 12 + 8 + 7
= 19
Remainder = 19
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