Advertisements
Advertisements
Question
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
Solution
Let x – 1 = 0, then x = 1
Substituting value of x in f(x)
f(x) = 2x3 – 3x2 + 7x – 8
= 2(1)3 – 3(1)2 + 7(1) – 8
= 2 x 1 – 3 x 1 + 7 x 1– 8
= 2 – 3 + 7 – 8
= -2
∴ Remainder = 2..
APPEARS IN
RELATED QUESTIONS
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 2
Using the Remainder Theorem find the remainders obtained when ` x^3 + (kx + 8 ) x + k ` is divided by x + 1 and x - 2 .
Hence find k if the sum of the two remainders is 1.
If the polynomial y3 − 5y2 + 7y + m is divided by y + 2 and the remainder is 50 then find the value of m.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x - 4
Find the remainder (without divisions) on dividing f(x) by x – 2, where f(x) = 2x3 – 7x2 + 3
Find ‘a’ if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leaves the same remainder when divided by x + 3.
Using the Remainder Theorem, factorise completely the following polynomial:
3x2 + 2x2 – 19x + 6
If on dividing 4x2 – 3kx + 5 by x + 2, the remainder is – 3 then the value of k is
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by x + 3
4x2 – kx + 5 leaves a remainder 2 when divided by x – 1. The value of k is ______.