Advertisements
Advertisements
Question
If on dividing 4x2 – 3kx + 5 by x + 2, the remainder is – 3 then the value of k is
Options
4
– 4
3
– 3
Solution
f(x) = 4x2 – 3kx + 5
g(x) = x + 2
Remainder = – 3
Let x + 2 = 0, then x = – 2
Now remainder will be
f(–2) = 4(–2)2 – 3k(–2) + 5
= 16 + 6k + 5
= 21 + 6k
∴ 21 + 6k = –3
⇒ 6k = –3 – 21
= –24
⇒ k = `(-24)/(6)` =–4
∴ k = –4.
APPEARS IN
RELATED QUESTIONS
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x.
Find the remainder when x3 – ax2 + 6x – a is divided by x – a.
Find the remainder when x4 – 3x2 + 2x + 1 is divided by x – 1.
What number should be added to 3x3 – 5x2 + 6x so that when resulting polynomial is divided by x – 3, the remainder is 8?
Find without division, the remainder in the following:
8x2 - 2x + 1 is divided by (2x+ 1)
What number should be added to polynomial f(x)= 12x3 + 16x2 - 5x - 8 so that the resulting polynomial is exactly divisible by (2x - 1) ?
use the rernainder theorem to find the factors of ( a-b )3 + (b-c )3 + ( c-a)3
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 3x3 + 7x2 – 5x + 1
Use the Remainder Theorem to factorise the following expression:
2x3 + x2 – 13x + 6
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 3x2 + 4x + 50; g(x) = x – 3
