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Question
Find the value of `2cos^-1 (1/2) + sin^-1 (1/2)`
Solution
y = `cos^-1 (1/2)`
cos y = `1/2 = cos pi/3`
y = `pi/3 ∈[0, pi]`
x = `sin^-1 (1/2)`
sin x = `1/2 = sin pi/3`
x = `pi/6 ∈[0, pi]`
`2cos^1(1/2) + sin^-1(1/2) = 2(pi/3) + pi/6`
= `(2pi)/3 + pi/6`
= `(4pi + pi)/6`
= `(5pi)/6`
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