Advertisements
Advertisements
Question
Find the value of 46 × 4−4.
Solution
46 × 4−4
= `4^(6 + (-4)) ...["a"^"m" xx "a"^"n" = "a"^"m"xx"n"]`
`= 4^(6 - 4)`
= 42
= 16
RELATED QUESTIONS
Evaluate :
`3^3 xx ( 243 )^(-2/3) xx 9^(-1/3)`
Evaluate :
`7^0 xx (25)^(-3/2) - 5^(-3)`
Simplify :
`( a + b )^(-1) . ( a^(-1) + b^(-1) )`
Simplify :
`( 3x^2 )^(-3) xx ( x^9 )^(2/3)`
Evaluate :
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
If 2160 = 2a. 3b. 5c, find a, b and c. Hence calculate the value of 3a x 2-b x 5-c.
If 1960 = 2a. 5b. 7c, calculate the value of 2-a. 7b. 5-c.
Simplify :
`( x^a/x^b)^( a^2 + ab + b^2 ) xx (x^b/x^c)^(b^2 + bc + c^2) xx (x^c/x^a)^( c^2 + ca + a^2 )`
Simplify:
`( x^a/x^-b )^( a^2 - ab + b^2 ) xx ( x^b/x^-c )^( b^2 - bc + c^2 ) xx ( x^c/x^-a )^( c^2 - ca + a^2 )`
If a = xm + n. yl ; b = xn + l. ym and c = xl + m. yn,
Prove that : am - n. bn - l. cl - m = 1