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Question
Find the values of a and b if the following polynomial is a perfect square
ax4 + bx3 + 361x2 + 220x + 100
Solution
Re-arrange the order we get
100 + 220x + 361x2 + bx3 + ax4 
Since it is a perfect square
b – 264 = 0
b = 264
a – 144 = 0
a = 144
∴ The value of a = 144 and b = 264
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