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Question
Find the values of the following polynomials at a = –2 and b = 3:
a2 + 2ab + b2
Solution
Given, a = –2 and b = 3
So, putting a = –2 and b = 3 in the given expressions, we get
a2 + 2ab + b2 = (–2)2 + 2(–2)(3) + (3)2
= 4 – 12 + 9
= 1
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