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Question
Find the value of x for which the numbers (5x + 2), (4x - 1) and (x + 2) are in AP.
Solution
It is given that (5x + 2),(4x -1) and (x+2) are in AP.
∴ (4x -1)- (5x +2) = (x+2) - (4x-1)
⇒ 4x -1 - 5x -2 = x+2 -4x +1
⇒ -x -3 = -3x+3
⇒ 3x -x=3+3
⇒2x=6
⇒ x =3
Hence, the value of x is 3.
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