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Question
Find y2 for the following function:
y = e3x+2
Solution
y = e3x+2
`y_1 = "dy"/"dx" = e^(3x + 2) "d"/"dx" (3x + 2)`
`= e^(3x + 2) (3(1) + 0)`
= `3e^(3x + 2)`
`y_2 = ("d"^2"y")/"dx"^2`
`= 3 ["d"/"dx" (e^(3x + 2))]`
= 3`[3e^(3x + 2)]`
= 9`e^(3x + 2)`
= 9y
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